Tamara is creating a model of a rectangle. She has 26 inches of yellow ribbon to use for the border of the rectangle. She wants the length, l, to be 3 inches greater than the width, w. Which system of equations could Tamara use to find the dimensions of a rectangle that uses all of the ribbon?
Let l and w be the length and width, respectively. Given that length is 3 inches greater than the width, it can be expressed as w + 3. Tamara has 26 inches of ribbon for the border which means that the perimeter of the rectangle should be 26. For rectangles,
P = 2L + 2W
Substituting the known values,
26 = 2 (w + 3) + 2w
Simplifying,
26 = 4w + 6
Thus, w is 5 inches and length is 8 inches.
Let
L-------> the length of the rectangle
W------> the width of the rectangle
we know that
the perimeter of the rectangle is equal to
\(P=2L+2W\)
\(P=26\ in\) -----> because Tamara's using the whole ribbon
so
\(26=2L+2W\) -------> equation A
\(L=W+3\) -------> equation B
Substitute equation B in equation A
\(26=2(W+3)+2W\)
\(26=2W+6+2W\)
\(4W=26-6\)
\(W=5\ in\)
find the value of L
\(L=W+3=5+3=8\ in\)
therefore
the answer is
The system of equations is
\(26=2L+2W\)
\(L=W+3\)