The hydrogen stored inside a large weather balloon has a mass of 13.558 g. What is the volume of this balloon if the density of hydrogen is 0.089 g/L?

Verified Answer :

AL2006


       (13.558 gm) · (1 L / 0.089 gm)  =  152.34 L  (rounded)
                                        
 (fraction equal to ' 1 ')  ^

Answer:

152.337 L

Explanation:

To calculate density using volume we use the common equation

\(D = \frac{m}{V} \\\)

where

D is the density

m is the mass

V is the volume

This equation can be manipulated to work out volume to:

\(V = \frac{m}{D} \\\\V = \frac{13.558g}{0.089g/L} \\\\V= 152.337 L\)