Verified Answer :

CmdrWinters

Written as an expression, the statement 'the sum of the square of a number and 34' would look like this:

\(n^{2} +34\)

Hope that helped! =)

calculista

the complete question is

The sum of the square of 2 number is 34. The first number is one less than twice the 2nd number. Find the number


Let

2x-1-------> the first number

x------->the second number


we know that

\((2x-1)^{2} +x^{2} =34\\ 4x^{2} -4x+1+x^{2} =34\\ 5x^{2} -4x-33=0\\ 5x^{2} -15x+11x-33=0\\ 5x*(x-3)+11*(x-3)=0\\ (5x+11)*(x-3)=0\)


therefore

\(x=3\\ 2x-1=5\)


the answer is

the numbers are

\(3,5\)

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