Explanation:
When an object is launched under the action of gravity, the path followed by it is called projectile motion. The horizontal component of velocity is given by :
\(v_x=u_i\ cos\theta\)
\(\theta\) is the angle made with horizontal
In case of projectile motion, the velocity of projectile is constant in horizontal direction. As a result the rate of change of velocity will be equal to 0. So, the horizontal acceleration of a ball that is launched horizontally is 0. Hence, this is the required solution.
