Verified Answer :

taskmasters

A quadratic equation has the general formula
expressed as:


ax^2 + bx

  • c = 0

This
equation can be solved by the quadratic formula which is expressed as:


x = ( -b
(+ or -) √(b^2 - 4ac) / 2a


From the
given equation,


a = 2

b = 3
c = -8

x = ( -3 (+ or -) √(3^2 - 4(2)(-8)) / 2(2)
x1 = 1.386
x2 = -2.886

carlosego

For this case we have the following quadratic function:
 \(0 = 2x^2 + 3x - 8\)
 Using the method of the resolver we have:
 \(x = \frac{-b +/- \sqrt{b^2-4ac} }{2a}\)
 Substituting values:
 \(x = \frac{-3 +/- \sqrt{3^2-4(2)(-8)} }{2(2)}\)
 Rewriting we have:
 \(x = \frac{-3 +/- \sqrt{9+64} }{4}\)
 \(x = \frac{-3 +/- \sqrt{73} }{4}\)
 Doing the calculations we have the results are:
 \(x1 = 1,386 x2 = -2,886\)
 Rounding the positive solution to the hundredth hundredth:
 \(x1 = 1.39\)
 Answer:
 The positive solution to the quadratic equation is:
 \(x = 1.39\)

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