we know that
The discriminant of the quadratic equation of the form
\(ax^{2} +bx+c=0\)
is equal to \((b^{2}-4ac )\)
we have
\(3 -4x = -6x^{2}\)
\(3 -4x = -6x^{2} \\ -6x^{2}+4x-3=0\)
in this problem
\(a=-6\\ b=4\\ c=-3\)
Substitute in the formula of discriminant
\((b^{2}-4ac )=4^{2}-4*(-6)*(-3)\\ =16-4*18\\ =-56\)
therefore
the answer is
the discriminant of the quadratic equation is \(-56\)
