Answer : The new pressure of gas will be, 25.176 kPa
Solution :
Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.
\(P\propto T\)
or,
\(\frac{P_1}{T_1}=\frac{P_2}{T_2}\)
where,
\(P_1\) = initial pressure of gas = 29.4 kPa
\(P_2\) = final pressure of gas = ?
\(T_1\) = initial temperature of gas = \(75^oC=273+75=348K\)
\(T_2\) = final temperature of gas = \(25^oC=273+25=298K\)
Now put all the given values in the above equation, we get the final pressure of gas.
\(\frac{29.4kPa}{348K}=\frac{P_2}{298K}\)
\(P_2=25.176kPa\)
Therefore, the new pressure of gas will be, 25.176 kPa
