For a Cosine function with amplitude =0.75 and period =10 , what is y(4) ?
From my research, the cosine function is:
y(t) = Acos(ωt)
Where:
A = amplitude = 0.75
ω = angular velocity = (2pi)/T = (2pi)/10 = 0.6283
Therefore:
y(4) = 0.75cos(0.62834)
y(4) = 0.61
We need to find a cosine function:
\(y(x)=acos(bx) \\ \\ where: \\ \\ \left|a\right|=Amplitude \\ \\ Period=\frac{2\pi}{b}\)
The amplitude represents half the distance between the maximum and minimum values of the function and the period goes from the x-value of one peak to the x-value of the next one. Therefore:
\(a=0.75 \\ \\ b=\frac{2\pi}{10}=\frac{\pi}{5}\)
Finally:
\(\boxed{y(x)=0.75cos(\frac{\pi}{5}x)}\)
And y(4) is:
\(y(4)=0.75cos(\frac{\pi}{5}\times 4) \\ \\ \therefore \boxed{y(4)=-0.60}\)