Verified Answer :

From my research, the cosine function is:

y(t) = Acos(ωt)

Where:
A = amplitude = 0.75
ω = angular velocity = (2pi)/T = (2pi)/10 = 0.6283

Therefore:

y(4) = 0.75cos(0.62834)
y(4) = 0.61

We need to find a cosine function:


\(y(x)=acos(bx) \\ \\ where: \\ \\ \left|a\right|=Amplitude \\ \\ Period=\frac{2\pi}{b}\)


The amplitude represents half the distance  between the maximum and minimum values of the function and the period goes from the x-value of one peak to the x-value of the next one. Therefore:


\(a=0.75 \\ \\ b=\frac{2\pi}{10}=\frac{\pi}{5}\)


Finally:


\(\boxed{y(x)=0.75cos(\frac{\pi}{5}x)}\)


And y(4) is:


\(y(4)=0.75cos(\frac{\pi}{5}\times 4) \\ \\ \therefore \boxed{y(4)=-0.60}\)