Using the following given values:
Object 1:
Mass = M1 = 2 kg
Velocity before collision = Vb1 = 20 m/s
Velocity after collision = Va1 = -5 m/s
Object 2:
Mass = M2 = 3 kg
Velocity before collision = Vb2 = -10 m/s
Velocity after collision = Va2 = ? m/s
Obtaining Va2 via law of conservation of momentum:
total momentum after collision = total momentum before collision
M1 Va1 + M2 Va2 = M1 Vb1 + M2 Vb2
2-5 + 3Va2 = 220 + 3-10
Va2 = 6.67
Total kinetic energy before collision:
KE1 = (1/2)M1Vb1^2 + (1/2)M2Vb2^2
KE1 = (1/2)2(20)^2 + (1/2)3(-10)^2
KE1 = 550 J
Total kinetic energy after collision:
KE2 = (1/2)M1Va1^2 + (1/2)M2Va2^2
KE2 = (1/2)2(-5)^2 + (1/2)3*(6.67)^2
KE2 = 91.73 J
Total kinetic energy lost:
Energy lost = KE1 - KE2 = 550 - 91.73 = 458.27 J
