Jeff is baking a cake. The recipe says that he has to mix 32 grams of vanilla powder to the flour. Jeff knows that 1 cup of that particular vanilla powder has a mass of 128 grams. He added two over three of a cup of vanilla powder to the flour. Should Jeff add more vanilla powder to make the exact recipe or did he go over and by what amount?

The situation above described that Jeff added two - thirds of 128 to the flour. The numerical value of (2/3)(128) is 85.33 grams. The recipe says to add only 32 grams of vanilla powder. Hence, Jeff went over the prescribed amount.

To determine the excess amount, subtract 32 from 85.33 which has a numerical value of 53.33 grams.

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Tringa0 Tringa0 · Answer 2 · 2020-01-06T06:15:06-05:00

Answer:

Jeff has add more vanilla powder to the exact recipe.

He had to start over again by only adding \(\frac{1}{4}\) cups of vanilla to the flour.

Step-by-step explanation:

1 cup of that particular vanilla powder has a mass of 128 grams

1 cup = 128 grams

Cups of vanilla added by Jeff = \(\frac{2}{3}\)

Mass of \(\frac{2}{3}\) cups of vanilla :

\(\frac{2}{3}\times 128 grams=\frac{128}{3} grams=85.33 grams\)

Mass of vanilla required = 32 grams

Cups of vanilla required =\(\frac{32}{128} =\frac{1}{4} cup\)

Jeff has already added 85.33 grams of vanilla which is greater the mass of 32 grams of vanilla. So, he had to start over again by only adding \(\frac{1}{4}\) cups of vanilla to the flour.