A plane takes off at an angle of elevation of 15° and travels in a straight line for 3,000 meters. What is the height of the plane above the ground at this instant?
Forming thw diagram, you have the length of the hypotenuse, and you want to find the height, which is the 'opposite length to the angle'
So using SOHCAHTOA
we have:
sin15 = height / 3000
height = 3000 sin 15
height = 776.46m
So, the height of the plane above the ground at this instant is 776.46m