The mass of the block m2 is 0.495kg
In order to get the mass of block 2 according to the given equation, we will use the formula below:
\(m_2=\frac{m_1(g-a)}{a+g\mu cos\theta + gsin\theta}\)
Given the following parameters
m1 - 0.7kg
g = 9.8m/s²
a = 0.2m/s²
\(\mu=0.2\)
\(\theta = 30^0\)
Substitute the given parameters into the formula as shown:
\(m_2=\frac{0.7(9.8-0.2)}{0.2+9.8\mu cos30 + 9.8sin30}\\m_2=\frac{0.7\times9.6}{0.2+ 8.4870+ 4.9}\\m_2=\frac{6.72}{13.587}\\m_2=0.495kg\)
Hence the mass of the block m2 is 0.495kg
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