Answer: The cubic function will be
\(x^3+3x^2-6x-18\)
Step-by-step explanation:
Since we have given that
the roots are
\(\sqrt{6},-\sqrt{6},-3\)
Since it has three roots , so it is a cubic function.
The cubic function is given by
\((x-\sqrt{6})(x+\sqrt{6})(x-(-3))\\\\=(x^2-(\sqrt{6})^2)(x+3)\\\\=(x^2-6)(x+3)\\\\=x^2(x+3)-6(x+3)\\\\=x^3+3x^2-6x-18\)
So, the cubic function will be
\(x^3+3x^2-6x-18\)
