Verified Answer :

Given a sequence; a₁,a₂,a₃...,an,
The common difference is d= a₂-a₁=a₃-a₂=a₄-a₃....

In this case: 
a₁=1.05
a₂=1.1

d=a₂-a₁=(1.1)-(1.05)=0.05

Answer: The common difference is 0.05. 

JeanaShupp

Answer: 0.05

Step-by-step explanation:

In the given sequence, the first term = 1.05

The second term = 1.1

The difference between first and second term =\(1.1-1.05=0.05\)

The third term = 1.15

The difference between second and third term =\(1.15-1.1=0.05\)

The fourth term = 1.2

The difference between third and fourth term =\(1.15-1.1=0.05\)

Hence, the common difference of the given sequence =0.05

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