Answer: \(6p^3 + 29p^2 + 22p – 21\)
Step-by-step explanation:
The given expression : \((2p + 7)(3p^2 + 4p - 3)\)
To find the product, we need to use the distributive property.
The distributive property is given by :-
\(a(b+c)=ab+ac\)
Then , the product will become:
\((2p + 7)3p^2 + (2p + 7)4p - (2p + 7)3\\\\=\\\\=(2p*3p^2 + 7*3p^2)+(2p*4p + 7*4p)-(2p*3 + 7*3)\\\\=6p^{2+1}+21p^2+8p^{1+1}+28p-6p-21........\text{Since }a^ma^n=a^{m+n}\\\\=6p^3+21p^2+8p^2+22p-21\\\\=6p^3 + 29p^2 + 22p - 21\)
