A tow truck exerts a net horizontal force of 1050 n on a 760-kg car. what is the acceleration of the car during this time?
Answer: The acceleration of the car during this time is 1.38 \(m/s^2\).
Explanation:
Force exerted on the two truck = 1050 N
Mass of the car = 760 kg
According to Newton's second law of Motion;
\(Force=Mass \times Acceleration\)
\(1050 N=760 kg\times Acceleration\)
\(Acceleration=\frac{1050 N}{760 kg}=1.38 m/s^2\)
The acceleration of the car during this time is 1.38 \(m/s^2\).