Verified Answer :

a = f/m

a= 1050/760

a= 1.38m/s^2

Answer: The acceleration of the car during this time is 1.38 \(m/s^2\).

Explanation:

Force exerted on the two truck = 1050 N

Mass of the car = 760 kg

According to Newton's second law of Motion;

\(Force=Mass \times Acceleration\)

\(1050 N=760 kg\times Acceleration\)

\(Acceleration=\frac{1050 N}{760 kg}=1.38 m/s^2\)

The acceleration of the car during this time is 1.38 \(m/s^2\).