In the following reaction, how many liters of o2 will produce 43.62 liters of co2 at stp? c3h8 5 o2 3 co2 4 h2o
The balanced chemical reaction:
C3H8 + 5O2 = 3CO2 + 4H2O
We are given the amount of the carbon dioxide to be produced. This will be the starting point of our calculations.
43.62 L CO2 ( 1 mol CO2 / 22.4 L CO2 ) (5 mol O2 / 3 mol CO2 ) (
22.4 L O2 / 1 mol O2) = 72.7 L O2
Answer: 72.7 L
Explanation:
\(C _3H_8+5O_2\rightarrow 3CO_2+4H_2O\)
As can be seen from the balanced chemical equation:
3 moles of carbon dioxide are produced by 5 moles of oxygen.
According to avogadro's law, 1 mole of every gas occupies 22.4 L at STP.
\(3\times 22.4=67.2L\) of carbon dioxide are produced by \(5\times 22.4=112L\) of oxygen at STP
Thus 43.62 L of carbon dioxide are produced by =\(\frac{112L}{67.2}\times 43.62=72.7L\) of oxygen at STP
Thus 72.7 liters of oxygen will produce 43.62 liters of carbon dioxide at STP.