The slope of a line is \(\frac{y_2 - y_1}{x_2 - x_1}\). We have the points (3, -2) and (1, 8). Let's substitute those into the formula.
\(\frac{8 - (-2)}{1-3}\)
subtracting a negative is the same as adding, so that makes our equation
\(\frac{8+2}{1-3}\)
\(\frac{10}{-2}\)
slope = -5
