Answer:
All polar coordinates of point P = (6, 31°) are \(P=(6,\frac{31\pi}{180}+2n\pi)\) and \(P=(-6,\frac{31\pi}{180}+(2n+1)\pi)\) where, n is an integer.
Step-by-step explanation:
The given polar coordinates of a point are
\(P=(6,31^{\circ})\)
If a point is defined as
\(P=(r,\theta)\)
Where, θ is in radian, then the polar coordinates of that points are
\((r,\theta)=(r,\theta+2n\pi)\)
\((r,\theta)=(-r,\theta+(2n+1)\pi)\)
Where, n is an integer.
The given point in radian form is
\(P=(6,31\times \frac{\pi}{180})\)
\(P=(6,\frac{31\pi}{180})\)
All polar coordinates of point P = (6, 31°) are
\(P=(6,\frac{31\pi}{180}+2n\pi)\)
\(P=(-6,\frac{31\pi}{180}+(2n+1)\pi)\)
Where, n is an integer.
