The solution of the given quadratic equation 6a² − a − 5 = 0 will be a ( 1 , -5 / 6 ).
What is a quadratic equation?
The polynomial having a degree of two or the maximum power of the variable in a polynomial will be 2 is defined as the quadratic equation and it will cut two intercepts on the graph at the x-axis.
The solution of the given equation is as follows:-
6a² − a − 5 = 0
Using the factorization formula:-
\(a = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\)
\(a=\dfrac{-(-1)\pm\sqrt{(-1)^2-(4\times 6\times -5}}{6\times 2}\)
\(a=\dfrac{1\pm\sqrt{121}}{12}\)
\(a=\dfrac{1\pm11}{12}\)
First, take the positive and then take the negative sign to calculate two values of a.
\(a=\dfrac{11+1}{12}=1\)
\(a=\dfrac{1-11}{12}=\dfrac{-10}{12}=\dfrac{-5}{6}\)
Therefore the solution of the given quadratic equation 6a² − a − 5 = 0 will be a ( 1 , -5 / 6 ).
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