This math question is under the Solid Mensuration topic. Let us recap the formulas of the volume of both the cylinder and the cone.
\(V_{cylinder}= \pi r^2h\)
\(V_{cone}= \frac{1}{3} \pi r^{2}h\)
So if the volume of the cylinder is 32.25 inches,
\(32.25=V_{cylinder}\)
Then,
\(32.25= \pi r^2h\)
So, to obtain the value of the volume of the cone is we simply multiply \(\frac{1}{3}\) to both of the sides of the equation.
\(\frac{1}{3} 32.25= \frac{1}{3} \pi r^2h\)
\(10.75= \frac{1}{3} \pi r^2h\)
\(10.75=V_{cone}\) [/tex]
So its value if the radius and its height is the same as to the cylinder is 10.75 cubic inches.
