Verified Answer :

taskmasters

The
balanced reaction is:

Mg(OH)2 +
2HCl = MgCl2 + 2H2O


We are
given the amount of calcium hydroxide for the reaction to use. This will be the
starting point for our calculations.

0.30 mol Mg(OH)2 ( 2 mol HCl / 1 mol Mg(OH)2 ) = 0.60 mol HCl

Answer : The number of moles of \(Mg(OH)_2\) required to neutralize 3.0 mole of HCl will be, 1.5 moles

Explanation : Given,

Moles of HCl = 3.0 mole

The balanced chemical reaction will be,

\(Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O\)

From the balanced chemical reaction, we conclude that

As, 2 moles of HCl neutralizes the 1 mole of \(Mg(OH)_2\)

So, 3.0 moles of HCl neutralizes the \(\frac{3.0}{2}=1.5\) moles of \(Mg(OH)_2\)

Therefore, the number of moles of \(Mg(OH)_2\) required to neutralize 3.0 mole of HCl will be, 1.5 moles

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