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S3ummejennieis
S3ummejennieis S3ummejennieis
  • 15-06-2016
  • Mathematics
Answered

Solve 4sin^2 x-3=0 find two values of sinx that satisfy this equation

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nobillionaireNobley
nobillionaireNobley nobillionaireNobley
  • 16-06-2016

\(4 sin^{2} x-3=0 \\ 4 sin^{2} x=3 \\ sin^{2} x= \frac{3}{4} \\ sinx= \pm \sqrt{ \frac{3}{4} } \\ sinx= \frac{ \sqrt{3} }{2} \ or \ sinx=- \frac{ \sqrt{3} }{2} \\ x= \frac{ \pi }{3} , \ \frac{2 \pi }{3} , \ \frac{4 \pi }{3} , \ \frac{5 \pi }{3}\)

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