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The balanced chemical reaction is:

HNO3 + NaOH = NaNO3 + H2O

We are given the amount and concentration of the reactants. The values given will be the starting point.

0.20 mol /L HNO3 (.015 L) (1 mol NaOH / 1 mol HNO3) = 0.003 mol NaOH

0.003 mol NaOH / 0.10 mol/ L NaOH = 0.03 L NaOH or 30 mL NaOH

Eduard22sly

The volume of 0.1 M NaOH needed to neutralize 15 mL of 0.2 M HNO₃ solution is 30 mL

Balanced equation

HNO₃ + NaOH —> NaNO₃ + H₂O

From the balanced equation above,

  • The mole ratio of the acid, HNO₃ (nA) = 1
  • The mole ratio of the base, NaOH (nB) = 1

How to determine the volume of NaOH

  • Concentration of base, NaOH (Cb) = 0.1 M
  • Volume of acid, HNO₃ (Va) = 15 mL
  • Concentration of acid, HNO₃ (Ca) = 0.2 M
  • Volume of base, NaOH (Vb) = ?

CaVa / CbVb = nA / nB

(0.2 × 15) / (0.1 × Vb) = 1

3 / 0.1 × Vb = 1

Cross multiply

0.1 × Vb = 3

Divide both side by 0.1

Vb = 3 / 0.1

Vb = 30 mL

Learn more about titration:

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