Verified Answer :

sleepyjess

(2n + 5k)^2 = (2n + 5k)(2n + 5k)
Here we need to use FOIL
First - 2n 2n = 4n^2
Outside - 2n 5k = 10nk
Inside - 5k 2n = 10nk
Last - 5k 5k = 25k^2

That gives us 4n^2 + 10nk + 10nk + 25k^2, we can combine 10nk + 10nk to give 20nk, and a final equaion of 4n^2 + 20nk + 25k^2

IloveDolphins

(x2 + y2)2 = (x2 – y2)2 + (2xy)2 is true for any x and y. That is an example.... so in your case i think it would be 

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