Find the absolute value of the complex number 5 - 4i
\(\sqrt{41}\)
Absolute value of a complex number \(a+ib=\sqrt{a^2+b^2}\)
Absolute value of \(5-4i=\sqrt{5^2+(-4)^2}\)
\(=\sqrt{41}\)
Find out more information about complex number here:
https://brainly.com/question/10251853?referrer=searchResults