Solve for c: A=1/2(b+c)h
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\(A=\frac{1}{2}(b+c)h\ \ \ \ |Divide\ by\ h\\\\ \frac{A}{h}=\frac{1}{2}(b+c)\ \ \ \ |Multiply\ by\ 2\\\\ \frac{2A}{h}=b+c\ \ \ \ |Subtract\ b\\\\ \frac{2A}{h}-b=c\\\\Solution\ is\ c=\frac{2A}{h}-b.\)
\(A= \frac{1}{2} (b+c)h \\ \\ 2A=(b+c)h \\ \\ \frac{2A}{h} =b+c \\ \\ \frac{2A}{h}-b=c\)
