Answered

Point C is located at (1, 2) and point D is located at (−4, −2). Find the x value for the point that is 1 over 4 the distance from point C to point D.


-0.25


3.25


-3.75


1.25

Verified Answer :

The answer is -0.25, When I graphed it that what I got.

Answer:

-0.25

Step-by-step explanation:

Coordinates of C  = \((x_{1} ,y_{1} )=(1,2)\)

Coordinates of D =  \((x_{2} ,y_{2} )=(-4,-2)\)

Let Coordinates of A= (x,y)

Since A point is located 1/4 the distance from C to D  

So the remaining distance from point A to D is 3/4

Thus the ratio of CA : AD = m:n=1:3

Now to find points of A we will use section formula i.e.

\(x=\frac{mx_{2}+nx_{1}}{m+n}\)

\(y=\frac{my_{2}+ny_{1}}{m+n}\)

Substituting the values:

\(x=\frac{1*-4+3*1}{1+3}\)

\(x=\frac{-1}{4}\)

\(x=-0.25\)

Thus Find the x value for the point that is 1 over 4 the distance from point C to point D is -0.25

Hence option a is correct

Related Questions