A rock falls from rest a vertical distance of 0.72 meter to the surface of a planet in 0.63 second. What is the magnitude of the acceleration due to gravity on the planet?
s = 0.72 m, t=0.63 s s = a · t² /2 0.72 m = a · (0.63 s )² / 2 a · 0.3969 s² = 1.44 m a = 1.44 m : 0.3969 s² = 3.628 m/s² The magnitude of the acceleration due to gravity on the planet is 3.628 m/s²
