An airplane flies due north at 100 m/s through a 30 m/s cross wind blowing from the east to the west. Determine the resultant velocity of the airplane.
Vf=√30²+100²
Vf=104 m/s
|Ф|=tan inverse of |100÷30|
Ф= 73 degrees
Therefore the resulting velocity of the airplaine is 104 m/s [ 73 degrees N of W]
Answer:
The resultant velocity of the airplane is 104.4 m/s.
Explanation:
It is given that,
Velocity of airplane, \(v_1=100\ m/s\) (due north)
Velocity of wind, \(v_2=30\ m/s\) (east to the west)
We need to find the resultant velocity of the airplane. The resultant velocity is given by :
\(v=\sqrt{v_1^2+v_2^2}\)
\(v=\sqrt{(100)^2+(30)^2}\)
v = 104.4 m/s
So, the resultant velocity of the airplane is 104.4 m/s. Hence, this is the required solution.