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Answered

A 45.0 kg ice skater needs a 25 N horizontal force to get moving on a smooth ice surface. What is the coefficient of friction between the ice and the skates?


a.1.80


c.0.18


b.0.057


d.0.56

Verified Answer :

HomertheGenius

The horizontal force : f = kN
k- coefficient of friction
k = f /N
N = m g = 45 kg * 9.81 m/s² = 441.45 N
k = 25 N : 441.45 N = 0.057
Answer C) 0.057

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