The series is convergent.
Explanation:\(\lim_{n \to \infty} \frac{1}{ 2^{n} } =\) 1/∞ = 0 ( it would be divergent if the answer was: -∞ or +∞ )
Sum of the infinite geometric series:
S∞ = a1 / ( 1-r )
a1 = 1 a2=\(\frac{1}{ \sqrt{2} }\) , a3=1/2, a4=\(\frac{1}{2 \sqrt{2} }\)...
r =\(\frac{1}{ \sqrt{2} }\)
S∞ =
