Solve the quadratic equation using factoring 9x2 - 16 = 0.
This is an example of difference of two squares meaning both of these variables are perfect squares. So when you factor this out you get (3x-4)(3x+4). Then since there's an equal sign you have to solve it. So it'd be 3x=4 divide it by 3 and you get 4/3 and 3x=-4 divide again you get -4/3. Your two final answers are 4/3 and -4/3.
\(9x^2-16=0\)
\(9x^2-16:\)
\(9x^2-16=(3x+4)(3x-4)\)
\((3x+4)(3x-4) :\)
Using the zero factor participle:
Solve: \((3x+4) = 0 : x = - \frac{4}{3}\)
\((3x-4) = 0 : x = \frac{4}{3}\)
The final solutions to the quadratic equation are:
\(x= -\frac{4}{3}\) and \(x = \frac{4}{3}\)
hope this helps!