Write an algebraic rule to describe the translation C(5, –4) C’(–2, 1)
We can solve this by using the formula:
(x, y) (x + a, y + b) = (5,-4) (-2,1)
So, plugging in the values and solving for a and b,
5 + a = -2
a = -8
-4 + b = 1
b = 5
Therefore, the translation is
(x,y) (x - 8, y +5)
Answer:
The required algebraic rule of translation is \((x,y)\rightarrow (x-7,y+5)\).
Step-by-step explanation:
The coordinates of a point are C(5, –4) and the coordinates of image are C’(–2, 1).
\(C(5,-4)\rightarrow C'(-2,1)\) .... (1)
Let the algebraic rule of translation is
\((x,y)\rightarrow (x+a,y+b)\) .... (2)
From (1) and (2) we get
\(x=5,y=-4\)
\(x+a=-2\)
\(5+a=-2\)
\(a=-2-5\)
\(a=-7\)
The value of a is -7.
\(y+b=1\)
\(-4+b=1\)
\(b=1+4\)
\(b=5\)
The value of b is 5.
The algebraic rule of translation is
\((x,y)\rightarrow (x-7,y+5)\)
Therefore the required algebraic rule of translation is \((x,y)\rightarrow (x-7,y+5)\).