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24.08 x 10^23 atoms of Boron (B) is equal to how many moles of Boron?

A2 moles
B4 moles
C12 moles
D6.02 x 10^23 moles

Verified Answer :

Willchemistry

1 mole ----------- 6.02 x 10²³ atoms
? mole ---------- 24.08 x 10²³ atoms

moles B = ( 24.08 x 10²³) x 1 / 6.02 x 10²³

moles B = 24.08 x 10²³ / 6.02 x 10²³

= 4 moles

Answer B

hope this helps!

Answer:

4 moles.

Explanation:

We know that the number of atoms in a mole of a substance = Avagadro's number = \(6.023X10^{23}\)

the moles of boron containing \(24.08X10^{23}\) atoms will be:

\(moles=\frac{numberofboronatoms}{avagadro'snumber}=\frac{24.08X10^{23}}{6.023X10^{23}}=3.99=4\)

Thus there will be four moles in the given atoms of boron.

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