The half-life of a radioactive isotope is 20.0 minutes. What is the total amount of a 1.00-gram sample of this sample of this isotope remaining after 1.00 hour?
The amount remaining is obtained using the half life data. The total amount remaining after one hour is equal to 1/( e^ (ln2/(20/60))*1). The final answer is 0.125 grams.
Answer: 0.125 grams
Explanation:
Radioactive decay follows first order kinetics.
Half-life of give isotope = 20 minutes
\(\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{20}=0.03465min^{-1}\)
\(N=N_o\times e^{-\lambda t}\)
N = amount left after time t= ?
\(N_0\) = initial amount = 1.0 g
\(\lambda\) = rate constant
t= time = 1 hour = 60 min
\(N=1.0\times e^{- 0.03465mi^{-1}\times 60min}\)
N=0.125g
Thus amount left after 1 hour is 0.125 grams