Multiple Choice:

A point moves on the x-axis in such a way that its velocity at time t (t>0) is given by v=lnt/t. At which value of t does v attain its maximum?

A1
Be^(1/2)
Ce
De^(3/2)
EThere is no maximum value for v.

Verified Answer :

dv/dt = \(\frac{t* \frac{1}{t}-1*lnt }{ t^{2} } = \\ = \frac{1-+lnt}{t^{2} }\)
Velocity attains its maximum at dv/dt = 0, or:
1 - ln t = 0
ln t = 1
\(log_{e}t= 1\)
t = e
Answer: C)