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A race car travels on a circular track at an average rate of 125 mi/h. The radius of the track is 0.320 miles. What is the centripetal acceleration of the car?

Verified Answer :

The centripetal acceleration is obtained from the quotient of the square of velocity and the radius. Hence, a= \(\frac{ v^{2} }{r}\). Substituting the give, v=125 mi/h and r=0.320 mi, the answer is equal to 48,828.125 mi/\(hr^{2}\).

Answer;

= 48,828.125 mi/hr²

Explanation and solution;

  • Centripetal acceleration is the rate of change of angular velocity. Centripetal acceleration occurs towards the center of the circular path along the radius of the circular path.
  • Centripetal acceleration is given by; V²/r ;

V = 125 mi/h and r = 0.320 miles

  • Thus; centripetal acceleration = 125²/0.320

                                                  =15625/0.320

                                                  = 48,828.125 mi/hr²

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