Answer:
Pythagoras Theorem
Step-by-step explanation:
For any triangle ABC, the law of cosine is given by
\(c^2=a^2+b^2-2ab\cos C\)
Now, let us suppose the triangle ABC is a right triangle having right angle at C.
Thus, C = 90°
Substituting this value in above formula
\(c^2=a^2+b^2-2ab\cos 90\)
We know that cos 90°= 0
Thus, the equation becomes
\(c^2=a^2+b^2-2ab\cdot0\\\\c^2=a^2+b^2\)
We can see that it reduces to Pythagoras Theorem.
Hence, we can conclude that law of cosines reduce to Pythagoras Theorem when dealing with a right triangle
