Answered

the equation below describes a circle. what are the coordinates of the center of the circle?

(x+5squared)+(y+2squared)=21 squared

Verified Answer :

Hagrid

Since, the equation involved is a circle let us clearly write the equation first:
\((x+5)^2+(y+2)^2=21^2\)

From the standard equation of the circle:
\((x-h)^2+(y-k)^2=r^2\)
\((h,k)=(x,y)\)

So from the equation given above, our x would be -5, and our y is equivalent to -2.
So the center of our circle is located at the point (-5,-2)

Answer:

(-5,-2)

Step-by-step explanation:

the equation involved is a circle let us clearly write the equation first:

From the standard equation of the circle:

So from the equation given above, our x would be -5, and our y is equivalent to -2.

So the center of our circle is located at the point (-5,-2)

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