Which statement is true about BF3, a nonpolar molecule? It has nonpolar bonds and a symmetrical structure. It has nonpolar bonds and an asymmetrical structure. It has polar bonds and a symmetrical structure. It has polar bonds and an asymmetrical structure. It has ionic bonds and symmetrical structure.
I think the correct answer is the first option. It has nonpolar bonds and a symmetrical structure. The structure of a BF3 molecule shows a symmetrical trigonal geometry. The net dipole moment of the molecule is zero therefore it is polar.
Answer: It has polar bonds and a symmetrical structure.
Explanation:
Formula used for calculating hybridization
\(:{\text{Number of electrons}} =\frac{1}{2}[V+N-C+A]\)
where, V = number of valence electrons present in central atom i.e. boron= 3
N = number of monovalent atoms bonded to central atom=3
C = charge of cation = 0
A = charge of anion = 0
\(BF_3\)
\({\text{Number of electrons}} =\frac{1}{2}[3+3-0+0]=3\)
The number of electrons is 3 that means the hybridization will be \(sp^2\) and the electronic geometry of the molecule will be trigonal planar.
Thus as there are no lone pair of electrons, there is no distortion and the molecule is symmetrical. The B-F bonds are polar due to electronegativity difference but the polarities cancel due to symmetrical structure.