In a circle with an 8-inch radius, a central angle has a measure of 60°. How long is the segment joining the endpoints of the arc cut off by the angle?
Given the radius, circumference can be solved by the equation, C = 2πr. The circumference of the circle above is C = 2π(8 in) = 16π in. To solve for the length of the segment joining the arc is the circumference times the ratio of central angle and 360 degrees.
Length of the segment = (16π in)(60/360) = 8/3 π in
Thus, the length of the segment is approximately 8.36 in.
Answer:
The length of segment joining the endpoints of the arc is \(8\ in\)
Step-by-step explanation:
we know that
In the triangle ABC
see the attached figure to better understand the problem
\(AC=BC\) -----> is the radius of the circle
\(m
\(m
Initially the triangle ABC is an isosceles triangle
Remember that
the sum of the internal angles of triangle must be equal to \(180\°\)
For this particular case, the isosceles triangle ABC becomes an equilateral triangle, as the three angles are equal to \(60\°\)
The equilateral triangle has three equal sides and tree equal angles
so
\(AC=BC=AB\)
Hence
The length of segment joining the endpoints of the arc is \(8\ in\)