Answer:
The area of the figure ABCD is \(25\ units^{2}\)
Step-by-step explanation:
we have
\(A(-3, 2), B(2, 2), C(2, -4), D(-3, -2)\)
using a graphing tool
Plot the figure
see the attached figure
The figure is a trapezoid
The area of the trapezoid is equal to
\(A=\frac{1}{2}(AD+BC)AB\)
Find the distance between the points in the graph
we have
\(AD=4\ units\)
\(BC=6\ units\)
\(AB=5\ units\)
substitute
\(A=\frac{1}{2}(4+6)5=25\ units^{2}\)
