3=0.03t^3+0.05^2 solve for t
I believe that the answer is 111203.703704=t
3=\(0.03t^{3}\) + \(0.05^{2}\)3=0.03\(t^{3} + 0.05^{2}\)3=\(0.003t^{3}\)+ 0.00253-0.0025=\(0.03t^{3}\)2.9975=\(0.03t^{3}\)\(t^{3} = \frac{2.9975}{0.03}\)t=4.64
