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How many moles are there in 987 grams of Ra(OH)2? id also love to know the simplest equation for converting moles --> so i could practice on my own :)

Verified Answer :

JoshEast

Mole = \(\frac{mass}{molar mass}\)

Mass of Radium Hydroxide = 987g
Molar Mass of \(Ra(OH) _{2}\) = ((226) + (2 16) + (2 1))
                                            =  260 g / mol

∴  Moles of \(Ra(OH) _{2}\) = \(\frac{987 g }{ 260 g / mol }\)
                                            = 3.796 mols

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