the area of a square is given by the expression x^2-12x+36 square inches. find an expression that represents the length of one side of the square in inches
the area of a square is A=L² where, L is the length of the square and A is the area of the square.
So,
\(L= \sqrt{A}\)..........we get this by square rooting on both sides in the formula
\(L= \sqrt{ x^{2} -12x+36}\)
\(L= \sqrt{ (x)^{2} -2*x*6+ (6)^{2} }\)..............(a-b)²=a²-2ab+b²
\(L= \sqrt{ (x-6)^{2} }\)..................................(a-b)²=a²-2ab+b²
\(L=x-6\)...............................square cancels square root
So, the expression that represents the length of one side of square is x - 6 inches.
The area of a square is the products of its dimensions.
The length of one side of the square is x - 6
The area is given as:
\(\mathbf{Area = x^2 -12x + 36}\)
Expand
\(\mathbf{Area = x^2 -6x - 6x + 36}\)
Factorize
\(\mathbf{Area = x(x -6) - 6(x - 6)}\)
Factor out x - 6
\(\mathbf{Area = (x -6) (x - 6)}\)
Express as squares
\(\mathbf{Area = (x -6)^2}\)
The length of a square is the square root of its area.
So, we have:
\(\mathbf{Length= \sqrt{(x -6)^2}}\)
\(\mathbf{Length= x -6}\)
Hence, the length of one side of the square is x - 6
Read more about squares at:
https://brainly.com/question/1658516