The factored form of the polynomial x² + 9x + 20 is ( x + 4 ) ( x + 5 )
Further explanation
Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :
D = b² - 4 a c
From the value of Discriminant , we know how many solutions the equation has by condition :
D < 0 → No Real Roots
D = 0 → One Real Root
D > 0 → Two Real Roots
Let us now tackle the problem!
Given :
\(x^2 + 9x + 20\)
To factor this form, we first look for the following operations:
_ + _ = 9
_ × _ = 20
To fill in the blanks, the matching numbers are :
4 + 5 = 9
4 × 5 = 20
Next, the above equation can be factorized into:
\(x^2 + 9x + 20\)
\(x^2 + 4x + 5x + 20\)
\((x^2 + 4x) + (5x + 20)\)
\(x(x + 4) + 5(x + 4)\)
\(\large {\boxed {(x + 4)(x + 5)} }\)
Learn more
- Solving Quadratic Equations by Factoring : https://brainly.com/question/12182022
- Determine the Discriminant : https://brainly.com/question/4600943
- Formula of Quadratic Equations : https://brainly.com/question/3776858
Answer details
Grade: High School
Subject: Mathematics
Chapter: Quadratic Equations
Keywords: Quadratic , Equation , Discriminant , Real , Number
