Verified Answer :

First get the equation into the form: Ax^2 + Bx + C = 0 (the quadratic equation)..

We do this by subtracting 10x both sides (to get it on the other side)..

9x^2 + 2 = 10x

9x^2 - 10x + 2 = 10x - 10x

9x^2 - 10x + 2 = 0

Now the discriminant is: b^2 - 4ac

The quadratic equation is Ax^2 + Bx + C = 0

Here, A = 9, B = -10 and C = 2 so plug them in...

(-10)^2 - 4 (9)(2)

= 100 - 4 (18)

= 100 - 72

= 28 <--- answer...

The discriminant of  \(9x^2+2=10x\) is 28.

The discriminant (d) of a quadratic equation \(ax^2+bx+c=0\) is given by :-

\(d=b^2-4ac\)

The given quadratic equation: \(9x^2+2=10x\)

Rewrite in the standard form, we get \(9x^2-10x+2=0\)

Here \(a=9, b=-10 , c=2\)

So, the discriminant of the equation will be :

\(d=(-10)^2-4(9)(2)\)

\(=100-72\)

\(=28\)

Therefore, the discriminant of  \(9x^2+2=10x\) is 28.

Learn more about discriminant:

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