What is the discriminant of 9x2 + 2 = 10x?
First get the equation into the form: Ax^2 + Bx + C = 0 (the quadratic equation)..
We do this by subtracting 10x both sides (to get it on the other side)..
9x^2 + 2 = 10x
9x^2 - 10x + 2 = 10x - 10x
9x^2 - 10x + 2 = 0
Now the discriminant is: b^2 - 4ac
The quadratic equation is Ax^2 + Bx + C = 0
Here, A = 9, B = -10 and C = 2 so plug them in...
(-10)^2 - 4 (9)(2)
= 100 - 4 (18)
= 100 - 72
= 28 <--- answer...
The discriminant of \(9x^2+2=10x\) is 28.
The discriminant (d) of a quadratic equation \(ax^2+bx+c=0\) is given by :-
\(d=b^2-4ac\)
The given quadratic equation: \(9x^2+2=10x\)
Rewrite in the standard form, we get \(9x^2-10x+2=0\)
Here \(a=9, b=-10 , c=2\)
So, the discriminant of the equation will be :
\(d=(-10)^2-4(9)(2)\)
\(=100-72\)
\(=28\)
Therefore, the discriminant of \(9x^2+2=10x\) is 28.
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