The balanced reaction
is:
4NH3 + 3O2 --> 2N2 + 6H2O
We
are given the amount of reactants to be used for the reaction. This
will be the starting point of our calculation.
83.7g of O2 ( 1 mol / 32 g) = 2.62 mol O2
2.81 moles of NH3
From the balanced reaction, we have a 4:3 ratio of the reactants. The limiting reactant would be oxygen. We will use the amount for oxygen for further calculations.
2.62 mol O2 (6 mol H2O / 3 mol O2) (18.02 g H2O / 1 mol H2O) = 94.42 g H2O
