Answer: The volume of iron occupied is \(0.572cm^3\)
Explanation:
The relationship between specific gravity and density of a substance is given as:
\(\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}\)
Specific gravity of iron = 7.87
Density of water = \(1.00g/cm^3\)
Putting values in above equation we get:
\(7.87=\frac{\text{Density of iron}}{1.00g/cm^3}\\\\\text{Density of iron}=7.87g/cm^3\)
To calculate volume of a substance, we use the equation:
\(\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}\)
Density of iron = \(7.87g/cm^3\)
Mass of iron = 4.50 g
Putting values in above equation, we get:
\(7.87g/cm^3=\frac{4.50g}{\text{Volume of iron}}\\\\\text{Volume of iron}=0.572cm^3\)
Hence, the volume of iron occupied is \(0.572cm^3\)
